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                [SCOI2011]棘手的操作                </h1>
                <p>时间限制：10s&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;  空间限制：128MB</p>			</div>
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                                <h3>题目描述</h3><p><p class="p0" style="margin-top: 0pt; margin-bottom: 0pt; text-indent: 21pt"><span style="font-size: 10.5pt; font-family: 'Times New Roman'; mso-spacerun: 'yes'">有<font face="Times New Roman">N</font><font face="宋体">个节点，标号从</font><font face="Times New Roman">1</font><font face="宋体">到</font><font face="Times New Roman">N</font><font face="宋体">，这</font><font face="Times New Roman">N</font><font face="宋体">个节点一开始相互不连通。第</font><font face="Times New Roman">i</font><font face="宋体">个节点的初始权值为</font><font face="Times New Roman">a[i]</font><font face="宋体">，接下来有如下一些操作：</font></span><span style="font-size: 10.5pt; font-family: 'Times New Roman'; mso-spacerun: 'yes'"><o:p></o:p></span></p>
<p class="p0" style="margin-top: 0pt; margin-bottom: 0pt"><span style="font-size: 10.5pt; font-family: 'Times New Roman'; mso-spacerun: 'yes'">U&nbsp;x&nbsp;y:</span><span style="font-size: 10.5pt; font-family: 'Times New Roman'; mso-spacerun: 'yes'"> </span><span style="font-size: 10.5pt; font-family: 'Times New Roman'; mso-spacerun: 'yes'">加一条边，连接第<font face="Times New Roman">x</font><font face="宋体">个节点和第</font><font face="Times New Roman">y</font><font face="宋体">个节点</font></span><span style="font-size: 10.5pt; font-family: 'Times New Roman'; mso-spacerun: 'yes'"><o:p></o:p></span></p>
<p class="p0" style="margin-top: 0pt; margin-bottom: 0pt"><span style="font-size: 10.5pt; font-family: 'Times New Roman'; mso-spacerun: 'yes'">A1&nbsp;x&nbsp;v:</span><span style="font-size: 10.5pt; font-family: 'Times New Roman'; mso-spacerun: 'yes'"> </span><span style="font-size: 10.5pt; font-family: 'Times New Roman'; mso-spacerun: 'yes'">将第<font face="Times New Roman">x</font><font face="宋体">个节点的权值增加</font><font face="Times New Roman">v</font></span><span style="font-size: 10.5pt; font-family: 'Times New Roman'; mso-spacerun: 'yes'"><o:p></o:p></span></p>
<p class="p0" style="margin-top: 0pt; margin-bottom: 0pt"><span style="font-size: 10.5pt; font-family: 'Times New Roman'; mso-spacerun: 'yes'">A2&nbsp;x&nbsp;v:</span><span style="font-size: 10.5pt; font-family: 'Times New Roman'; mso-spacerun: 'yes'"> </span><span style="font-size: 10.5pt; font-family: 'Times New Roman'; mso-spacerun: 'yes'">将第<font face="Times New Roman">x</font><font face="宋体">个节点所在的</font>连通块的所有节点的权值都增加<font face="Times New Roman">v</font></span><span style="font-size: 10.5pt; font-family: 'Times New Roman'; mso-spacerun: 'yes'"><o:p></o:p></span></p>
<p class="p0" style="margin-top: 0pt; margin-bottom: 0pt"><span style="font-size: 10.5pt; font-family: 'Times New Roman'; mso-spacerun: 'yes'">A3&nbsp;v:</span><span style="font-size: 10.5pt; font-family: 'Times New Roman'; mso-spacerun: 'yes'"> </span><span style="font-size: 10.5pt; font-family: 'Times New Roman'; mso-spacerun: 'yes'">将所有节点的权值都增加<font face="Times New Roman">v</font></span><span style="font-size: 10.5pt; font-family: 'Times New Roman'; mso-spacerun: 'yes'"><o:p></o:p></span></p>
<p class="p0" style="margin-top: 0pt; margin-bottom: 0pt"><span style="font-size: 10.5pt; font-family: 'Times New Roman'; mso-spacerun: 'yes'">F1&nbsp;x:</span><span style="font-size: 10.5pt; font-family: 'Times New Roman'; mso-spacerun: 'yes'"> </span><span style="font-size: 10.5pt; font-family: 'Times New Roman'; mso-spacerun: 'yes'">输出第<font face="Times New Roman">x</font><font face="宋体">个节点当前的权值</font></span><span style="font-size: 10.5pt; font-family: 'Times New Roman'; mso-spacerun: 'yes'"><o:p></o:p></span></p>
<p class="p0" style="margin-top: 0pt; margin-bottom: 0pt"><span style="font-size: 10.5pt; font-family: 'Times New Roman'; mso-spacerun: 'yes'">F2&nbsp;x:</span><span style="font-size: 10.5pt; font-family: 'Times New Roman'; mso-spacerun: 'yes'"> </span><span style="font-size: 10.5pt; font-family: 'Times New Roman'; mso-spacerun: 'yes'">输出第<font face="Times New Roman">x</font><font face="宋体">个节点所在的连通块中，权值最大的节点的权值</font></span><span style="font-size: 10.5pt; font-family: 'Times New Roman'; mso-spacerun: 'yes'"><o:p></o:p></span></p>
<p class="p0" style="margin-top: 0pt; margin-bottom: 0pt"><span style="font-size: 10.5pt; font-family: 'Times New Roman'; mso-spacerun: 'yes'">F3:</span><span style="font-size: 10.5pt; font-family: 'Times New Roman'; mso-spacerun: 'yes'"> </span><span style="font-size: 10.5pt; font-family: 'Times New Roman'; mso-spacerun: 'yes'">输出所有节点中，权值最大的节点的权值</span><span style="font-size: 10.5pt; font-family: 'Times New Roman'; mso-spacerun: 'yes'"><o:p></o:p></span></p>
<p class="p0" style="margin-top: 0pt; margin-bottom: 0pt"><span style="font-size: 10.5pt; font-family: 'Times New Roman'; mso-spacerun: 'yes'"><o:p></o:p></span></p>
<!--EndFragment--></p><hr/><h3>输入格式</h3><p><p class="p0" style="margin-top: 0pt; margin-bottom: 0pt"><span style="font-size: 10.5pt; font-family: 'Times New Roman'; mso-spacerun: 'yes'"><o:p></o:p></span>&nbsp;</p>
<p class="p0" style="margin-top: 0pt; margin-bottom: 0pt; text-indent: 20.25pt"><span style="font-size: 10.5pt; font-family: 'Times New Roman'; mso-spacerun: 'yes'">输入的第一行是一个整数<font face="Times New Roman">N</font><font face="宋体">，代表节点个数。</font></span><span style="font-size: 10.5pt; font-family: 'Times New Roman'; mso-spacerun: 'yes'"><o:p></o:p></span></p>
<p class="p0" style="margin-top: 0pt; margin-bottom: 0pt; text-indent: 20.25pt"><span style="font-size: 10.5pt; font-family: 'Times New Roman'; mso-spacerun: 'yes'">接下来一行输入<font face="Times New Roman">N</font><font face="宋体">个整数，</font><font face="Times New Roman">a[1],&nbsp;a[2],&nbsp;&hellip;,&nbsp;a[N]</font><font face="宋体">，代表</font><font face="Times New Roman">N</font><font face="宋体">个节点的初始权值。</font></span><span style="font-size: 10.5pt; font-family: 'Times New Roman'; mso-spacerun: 'yes'"><o:p></o:p></span></p>
<p class="p0" style="margin-top: 0pt; margin-bottom: 0pt; text-indent: 20.25pt"><span style="font-size: 10.5pt; font-family: 'Times New Roman'; mso-spacerun: 'yes'">再下一行输入一个整数<font face="Times New Roman">Q</font><font face="宋体">，代表接下来的操作数。</font></span><span style="font-size: 10.5pt; font-family: 'Times New Roman'; mso-spacerun: 'yes'"><o:p></o:p></span></p>
<p class="p0" style="margin-top: 0pt; margin-bottom: 0pt; text-indent: 20.25pt"><span style="font-size: 10.5pt; font-family: 'Times New Roman'; mso-spacerun: 'yes'">最后输入<font face="Times New Roman">Q</font><font face="宋体">行，每行的格式如题目描述所示。</font></span><span style="font-size: 10.5pt; font-family: 'Times New Roman'; mso-spacerun: 'yes'"><o:p></o:p></span></p>
<p class="p0" style="margin-top: 0pt; margin-bottom: 0pt; text-indent: 21pt"><span style="font-size: 10.5pt; font-family: 'Times New Roman'; mso-spacerun: 'yes'"><o:p></o:p></span></p></p><hr/><h3>输出格式</h3><p><p class="p0" style="margin-top: 0pt; margin-bottom: 0pt; text-indent: 21pt"><span style="font-size: 10.5pt; font-family: 'Times New Roman'; mso-spacerun: 'yes'">对于操作<font face="Times New Roman">F1,&nbsp;F2,&nbsp;F3</font><font face="宋体">，输出对应的结果，每个结果占一行。</font></span><span style="font-size: 10.5pt; font-family: 'Times New Roman'; mso-spacerun: 'yes'"><o:p></o:p></span></p>
<p class="p0" style="margin-top: 0pt; margin-bottom: 0pt; margin-left: 21pt"><span style="font-size: 10.5pt; font-family: 'Times New Roman'; mso-spacerun: 'yes'"><o:p></o:p></span></p></p><hr/><h3>样例输入</h3><pre>3

0 0 0

8

A1 3 -20

A1 2 20

U 1 3

A2 1 10

F1 3

F2 3

A3 -10

F3

</pre><hr/><h3>样例输出</h3><pre>
-10

10

10

</pre><hr/><h3>提示</h3><p><p><br />
&nbsp;对于30%的数据，保证 N&lt;=100，Q&lt;=10000</p>
<p>对于80%的数据，保证 N&lt;=100000，Q&lt;=100000</p>
<p>对于100%的数据，保证 N&lt;=300000，Q&lt;=300000</p>
<p>对于所有的数据，保证输入合法，并且 -1000&lt;=v, a[1], a[2], &hellip;, a[N]&lt;=1000<br />
</p></p><hr/><h3>题目来源</h3><p>Day2</p>
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